Question

Answer 1

Ta có: \(\left|2-x\right|+\left|x-2\right|=\frac14\)

=>\(\left|x-2\right|+\left|x-2\right|=\frac14\)

=>\(2\left|x-2\right|=\frac14\)

=>\(\left|x-2\right|=\frac18\)

=>\(\left[\begin{array}{l}x-2=\frac18\\ x-2=-\frac18\end{array}\right.\Rightarrow\left[\begin{array}{l}x=\frac18+2=\frac{17}{8}\\ x=2-\frac18=\frac{15}{8}\end{array}\right.\)