Question

Answer 1

\(\left|x-1\right|\)≥0; \(\left|2x-6\right|\)≥0

=>\(\left|x-1\right|\)+\(\left|2x-6\right|\)≥0

mà \(\left|x-1\right|+\left|2x-6\right|=8\)

=>x-1=8 và 2x-6=8

=> x=9 và x=7

=>x lần lượt là 9 và 7

Answer 2

help

Answer 3

\(\left|x-1\right|+\left|2x-6\right|=8\\ \Leftrightarrow\left[{}\begin{matrix}x-1+2x-6=8\\-\left(x-1\right)+2x-6=8\\x-1-\left(2x-6\right)=8\\-\left(x-1\right)-\left(2x-6\right)=8\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=5\\x=13\\x=-3\\x=-\dfrac{1}{3}\end{matrix}\right.\)