Question

Answer 1

61.

ĐK: \(x\ne\dfrac{\pi}{2}+k\pi\)

\(tanx=\sqrt{3}\)

\(\Leftrightarrow x=\dfrac{\pi}{3}+k\pi\)

Vì \(x=\dfrac{\pi}{3}+k\pi\in\left(0;\pi\right)\Rightarrow-\dfrac{1}{3}\le k\le\dfrac{2}{3}\Rightarrow k=0\Rightarrow x=\dfrac{\pi}{3}\)

62. Tương tự

Answer 2

63.

ĐK: \(x\ne\dfrac{\pi}{2}+k\pi\)

\(cotx=-\sqrt{3}\)

\(\Leftrightarrow cotx=cot\left(-\dfrac{\pi}{6}\right)\)

\(\Leftrightarrow x=-\dfrac{\pi}{6}+k\pi\)

Vì \(x=-\dfrac{\pi}{6}+k\pi\in\left(0;\dfrac{3\pi}{2}\right)\Rightarrow k=1\Rightarrow x=\dfrac{5\pi}{6}\)