Bài 2
A, 2x(2x-3)
B, xy(x^2-2xy+5)
C, 2x(x+1)(x+2)
D, 2/5.(y-1)(x+y)
E, (x-1)[2(x-1)^2-5(x-1)-1]
F, (y-x)[x(y-x)^2-y(y-x)-xy]
G, (x+y)(xy-2)
G, (x-y)[(x+y)^2-y^2]
Bài 3:
a) Ta có: \(4\left(x-2\right)^2+xy-2y\)
\(=4\left(x-2\right)^2+y\left(x-2\right)\)
\(=\left(x-2\right)\left(4x-8+y\right)\)
b) Ta có: \(x\left(x-y\right)^3-y\left(y-x\right)^2-y^2\left(x-y\right)\)
\(=x\left(x-y\right)^3-y\left(x-y\right)^2-y^2\left(x-y\right)\)
\(=\left(x-y\right)\left[x\left(x-y\right)^2-y\left(x-y\right)-y^2\right]\)
c) Ta có: \(x^2y-xy^2-3x+3y\)
\(=xy\left(x-y\right)-3\left(x-y\right)\)
\(=\left(x-y\right)\left(xy-3\right)\)
d) Ta có: \(x\left(x+y\right)^2-y\left(x+y\right)^2+xy-x^2\)
\(=\left(x+y\right)^2\cdot\left(x-y\right)-x\left(x-y\right)\)
\(=\left(x-y\right)\left(x^2+2xy+y^2-x\right)\)
Bài 2:
a) \(4x^2-6x=2x\left(2x-3\right)\)
b) \(x^3y-2x^2y+5xy=xy\left(x^2-2x+5\right)\)
c) \(2x^2\left(x+1\right)+4x\left(x+1\right)=2x\left(x+1\right)\left(x+2\right)\)
d) \(\dfrac{2}{5}x\left(y-1\right)-\dfrac{2}{5}y\left(1-y\right)=\dfrac{2}{5}\left(y-1\right)\left(x+y\right)\)
