Vì \(\left|a\right|\le1;\left|b-1\right|\le2\)

\(=>\left|a\right|\cdot\left|b-1\right|=\left|ab-a\right|\le2\)

Áp dụng BĐT \(\left|x\right|+\left|y\right|\ge\left|x+y\right|\) ta có:

\(\left|a-c+ab-a\right|\le\left|a-c\right|+\left|ab-a\right|=2+3=5\)

\(=>\left|ab-c\right|\le5\)

bạn nên rút gọn 36/48 = 3/4

\(-\sqrt{24}\cdot\sqrt{0,18}\)

\(=-1\cdot\sqrt{24\cdot0,18}\)

\(=-1\cdot\sqrt{\dfrac{54}{25}}\)

\(=\dfrac{-\sqrt{54}}{5}\)

Chùa Tây Phương bạn ạ!

ta có:

a - b = 18

=> 2a - 2b = 36

mà 2a = 5b

=> 5b - 2b = 36

=> 3b = 36

=> b = 12

Ta có:

a - b = 18

=> a - 12 = 18

=> a = 30

Vậy a = 30, b = 12

2 hàng cây trung nhau 2 cây nha 

x là cây

x x x x

x x x

x    x

b) \(\left(2x-1\right)^2-\dfrac{25}{4}=0\)

\(\left(2x-1\right)^2=\dfrac{25}{4}\)

\(\left(2x-1\right)^2=\left(\dfrac{5}{4}\right)^2=\left(-\dfrac{5}{4}\right)^2\)

TH1:

\(2x-1=\dfrac{5}{4}\)

\(2x=\dfrac{9}{4}\)

\(x=\dfrac{9}{8}\)

TH2:

\(2x-1=-\dfrac{5}{4}\)

\(2x=-\dfrac{1}{4}\)

\(x=-\dfrac{1}{8}\)

Vậy \(x\in\left\{-\dfrac{1}{8};\dfrac{9}{8}\right\}\)

a) \(5x-1=2x-4\)

\(3x+3=0\)

\(3x=-3\)

\(x=-1\)

Vậy \(x=-1\)