pthh: \(Fe+2HCl--->FeCl_2+H_2\uparrow\)
a. \(n_{Fe}=\dfrac{11,2}{56}=0,2\left(mol\right)\)
\(\Rightarrow n_{H_2}=0,2\left(mol\right)\)
\(\Rightarrow V_{H_2}=0,2.24,79=4,958\left(l\right)\)
b. \(n_{FeCl_2}=0,2\left(mol\right)\)
\(\Rightarrow m_{FeCl_2}=0,2.127=25,4\left(g\right)\)
c. \(n_{HCl}=2.0,2=0,4\left(mol\right)\)
\(\Rightarrow m_{HCl}=0,4.36,5=14,6\left(g\right)\)