x2 - x - 6 = 0
⇒ x2 + 2x - 3x - 6 = 0
⇒ x.(x + 2) - 3.(x + 2) = 0
⇒ (x - 3).(x + 2) = 0
\(\Rightarrow\left[{}\begin{matrix}x+2=0\\x-3=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=-2\\x=3\end{matrix}\right.\)
tìm x
a) x^2 - x = x - 1
b) (x^2 - 36) - (x+6) = 0
c) (2x-1)^2 - (4x^2 - 1)= 0
d) x^2(x^2 - 4) - (x^2 - 4 ) = 0
(x^2+x)^2+(x^2+x)-6=0
tìm x
a)(x+6)^2-x(x+9)=0
b)6x(2x+5)-(3x+4)(4x-3)=9
c)2x(8x+3)-(4x+1)=13
d)(x-4)^2-x(x+4)=0
e)(x-2)^2-(2x+3)(x-2)=0Tìm x,biết:
a) x+5x^2=0
b)x+1=(x+1)^2
c)x^3+x=0
d)4x^2-4x=-1
e) 8x^3+12x^2+6x+1=0
f)x^3+5x-6=0
g)2y^3-3y^2-5y=0
h)2x(x+5)-x^3-5x^2=0
Mn giúp mk vs nha.
Tìm x, biết
2x3-50=0
x2-5x=-6
(2x-1)2-(3x+5)=0
d, 4x2-20x+25=0
e,(3x-1)2-(x-2)2=0
Tìm x :
a)(x+2)3 -x2 (x+6)=-4
b)(x-3)2 -5x + 15=0
Tìm x
a)1/27x3 -125=0
b)x2 -7x +6 =0
c) 3x2 -7x +4=0
tìm x biết
1,\(x^2+x=0\)
1,\(x^2-10x=25\)
3\(\left(x+2\right)^2=x+2\)
4,\(\left(x-6\right)^2-x^2+36=0\)
5\(\left(3x-1\right)^3-\left(5x-2\right)^3-\left(1-2x\right)^3=0\)
x3 + 9x2 + 27x + 27 = 0
( x - 2 ) x - x2 (x - 6) = 4
27x3 - 27x2 + 9x - 1 = 8
(x - 1 )3 - (x + 3) . (
