ĐKXĐ: \(a\ne\left\{-\frac{4}{3};-4\right\}\)
\(\frac{3a+2}{3a+4}+\frac{a-2}{a+4}=2\)
\(\Leftrightarrow1-\frac{2}{3a+4}+1-\frac{6}{a+4}=2\)
\(\Leftrightarrow\frac{1}{3a+4}+\frac{3}{a+4}=0\)
\(\Leftrightarrow a+4+3\left(3a+4\right)=0\)
\(\Leftrightarrow10a+16=0\Rightarrow a=-\frac{8}{5}\)