\(y=\dfrac{2x-5}{3x-1}\in Z\Rightarrow\dfrac{3\left(2x-5\right)}{3x-1}\in Z\)
\(\Rightarrow\dfrac{6x-15}{3x-1}\in Z\Rightarrow2-\dfrac{13}{3x-1}\in Z\)
\(\Rightarrow13⋮3x-1\Rightarrow3x-1=\left\{-13;-1;1;13\right\}\)
\(\Rightarrow x=\left\{-4;0\right\}\)
Có 2 điểm có tọa độ nguyên