C= 3√45+29√2+3√45−29√2
⇔\(C^3=45+29\sqrt{2}+45-29\sqrt{2}+3\sqrt[3]{45+29\sqrt{2}}.\sqrt[3]{45-29\sqrt{2}}\left(\sqrt[3]{45+29\sqrt{2}}+\sqrt[3]{45-29\sqrt{2}}\right)\\ C^3=90+3\sqrt[3]{343}.C\\ C^3=90+21C\\ C^3-21C-90=0\\ C^3-36C+15C-90\\ C\left(C-6\right)\left(C+6\right)+15\left(C-6\right)=0\\ \left(C-6\right)\left[C\left(C+6\right)+15\right]=0\\ \left(C-6\right)\left(C^2+6C+15\right)=0\\ \)
Mà C2+6C+15=(C+3)2+6 > 0
Nên C-6=0
⇒C=6