Question

tính B=\(\left(x^{2007}+3x^{2006}-1\right)^{2007}\) tại x =-3

Answer 1

B=\(\left(x^{2007}+3x^{2006}-1\right)^{2007}\)

\(B=\left[\left(-3^{2007}\right)+3\left(-3^{2006}\right)-1\right]^{2007}\)

\(B=\left[\left(-3^{2007}\right)+3.3^{2006}-1\right]^{2007}\)

\(B=\left[\left(-3^{2007}\right)+3^{2007}-1\right]^{2007}\)

\(B=\left(-1\right)^{2007}=\left(-1\right)\)

Answer 2

Ta có: \(B=\left(x^{2007}+3x^{2006}-1\right)^{2007}\)

Thay x = -3 vào B ta có:

\(B=\left(\left(-3\right)^{2007}+3\left(-3\right)^{2006}-1\right)^{2007}\)

=>\(B=\left(\left(-3\right)^{2007}+3\cdot3^{2006}-1\right)^{2007}\)

=>\(B=\left(\left(-3\right)^{2007}+3^{2007}-1\right)^{2007}\)

=>\(B=\left(0-1\right)^{2007}\)

\(=>B=\left(-1\right)^{2007}=-1\)