sai đề phép cuối 1/2016*(1+2+...+2016)
Đúng 0
Bình luận (0)
Đại số lớp 8
Các câu hỏi tương tự
Tính:
\(\frac{1}{x.\left(x+1\right)}+\frac{1}{\left(x+1\right).\left(x+2\right)}+\frac{1}{\left(x+2\right).\left(x+3\right)}+\frac{1}{\left(x+3\right).\left(x+4\right)}+\frac{1}{\left(x+4\right).\left(x+5\right)}+\frac{1}{x+5}\)
Rút gọn \(\frac{1}{\left(x+y\right)^3}.\left(\frac{1}{x^3}+\frac{1}{y^3}\right)+\frac{3}{\left(x+y\right)^5}.\left(\frac{1}{x^2}+\frac{1}{y^2}\right)+\frac{6}{\left(x+y\right)^5}.\left(\frac{1}{x}+\frac{1}{y}\right)\)
\(\left(\frac{1}{x+1}-\frac{3}{x^3+1}+\frac{3}{x^2-x+1}\right).\frac{3x^2-3x+3}{\left(x+1\right)\left(x+2\right)}-\frac{2x-2}{x^2+2x}\) thực hiện phép tính
tính : \(\frac{1}{2}.\left(1+\frac{1}{1.3}\right).\left(1+\frac{1}{2.4}\right).\left(1+\frac{1}{3.5}\right).....\left(1+\frac{1}{2015.2017}\right)\)
1 . Thực hiện phép tính :
a ) frac{1}{x-1}+frac{1}{left(1-xright)left(2-xright)}+frac{1}{left(x-2right)left(x-3right)}
b ) frac{4-2x+x^2}{2+x}-2-x
c ) left(frac{1}{1+x}+frac{2x}{1-x^2}right)left(frac{1}{x}-1right)
d ) left(frac{x+1}{x-1}-frac{x-1}{x+1}right):left(frac{1}{x+1}-frac{x}{1-x}+frac{2}{x^2-1}right)
giúp với câu nào cũng đc ! mk sẽ tick cho 3 cái !!!
Đọc tiếp
1 . Thực hiện phép tính :
a ) \(\frac{1}{x-1}+\frac{1}{\left(1-x\right)\left(2-x\right)}+\frac{1}{\left(x-2\right)\left(x-3\right)}\)
b ) \(\frac{4-2x+x^2}{2+x}-2-x\)
c ) \(\left(\frac{1}{1+x}+\frac{2x}{1-x^2}\right)\left(\frac{1}{x}-1\right)\)
d ) \(\left(\frac{x+1}{x-1}-\frac{x-1}{x+1}\right):\left(\frac{1}{x+1}-\frac{x}{1-x}+\frac{2}{x^2-1}\right)\)
giúp với câu nào cũng đc ! mk sẽ tick cho 3 cái !!! 
Đơn giản biểu thức :\(A=\frac{1}{\left(a+b\right)^3}\left(\frac{1}{a^3}+\frac{1}{b^3}\right)+\frac{3}{\left(a+b\right)^4}+\left(\frac{1}{a^2}+\frac{1}{b^2}\right)+\frac{b}{\left(a+b\right)^5}+\left(\frac{1}{a}+\frac{1}{b}\right)\)
GIÚP MÌNH NHA!... 
giải phương trình
1. frac{2x+3}{5x-3}-frac{3}{4x-6}frac{2}{5}
2. frac{1}{x-1}-frac{7}{x-2}frac{1}{left(x-1right)left(2-xright)}
3. x+frac{x-1}{x-2}3+frac{1}{x-2}
4. frac{x+1}{x-3}-frac{1}{x-1}frac{2}{left(x-1right)left(x-3right)}
5. frac{2x-1}{x+1}+frac{x}{left(x-1right)left(x-2right)}frac{6x-2}{x-2}
Đọc tiếp
giải phương trình
1. \(\frac{2x+3}{5x-3}\)-\(\frac{3}{4x-6}\)=\(\frac{2}{5}\)
2. \(\frac{1}{x-1}\)-\(\frac{7}{x-2}\)=\(\frac{1}{\left(x-1\right)\left(2-x\right)}\)
3. x+\(\frac{x-1}{x-2}\)=3+\(\frac{1}{x-2}\)
4. \(\frac{x+1}{x-3}\)-\(\frac{1}{x-1}\)=\(\frac{2}{\left(x-1\right)\left(x-3\right)}\)
5. \(\frac{2x-1}{x+1}+\frac{x}{\left(x-1\right)\left(x-2\right)}=\frac{6x-2}{x-2}\)
giải jùm vs
Rút gọn Pthức:
A= \(\left(\frac{1}{x+1}-\frac{3}{x^3+1}+\frac{3}{x^2+x+1}\right)\frac{3x^2-3x+3}{\left(x+1\right)\left(x+2\right)}-\frac{2x-2}{x^2+2x}\)
Thực hiện phép tính:
a) \(A=\frac{x^2-yz}{1+\frac{y+z}{x}}+\frac{y^2-zx}{1+\frac{z+x}{y}}+\frac{z^2-xy}{1+\frac{x+y}{z}}\)
b) \(B=\frac{2}{3}.\left[\frac{1}{1+\frac{\left(2x+1\right)^2}{3}}+\frac{1}{1+\frac{\left(2x-1\right)^2}{3}}\right]\)