giải phương trình
1. \(\frac{2x+3}{5x-3}\)-\(\frac{3}{4x-6}\)=\(\frac{2}{5}\)
2. \(\frac{1}{x-1}\)-\(\frac{7}{x-2}\)=\(\frac{1}{\left(x-1\right)\left(2-x\right)}\)
3. x+\(\frac{x-1}{x-2}\)=3+\(\frac{1}{x-2}\)
4. \(\frac{x+1}{x-3}\)-\(\frac{1}{x-1}\)=\(\frac{2}{\left(x-1\right)\left(x-3\right)}\)
5. \(\frac{2x-1}{x+1}+\frac{x}{\left(x-1\right)\left(x-2\right)}=\frac{6x-2}{x-2}\)
2. \(\frac{1}{x-1}-\frac{7}{x-2}=\frac{1}{\left(x-1\right)\left(2-x\right)}\) (ĐKXĐ:\(x\ne1,x\ne2\))
\(\Leftrightarrow\frac{1}{x-1}+\frac{7}{2-x}=\frac{1}{\left(x-1\right)\left(2-x\right)}\)
\(\Leftrightarrow\frac{2-x+7\left(x-1\right)}{\left(x-1\right)\left(2-x\right)}=\frac{1}{\left(x-1\right)\left(2-x\right)}\)
\(\Rightarrow2-x+7\left(x-1\right)=1\)
\(\Leftrightarrow2-x+7x-7=1\)
\(\Leftrightarrow-x+7x=1-2+7\)
\(\Leftrightarrow6x=6\)
\(\Leftrightarrow x=1\) (Không thỏa mãn ĐKXĐ)
Vậy phương trình trên vô nghiệm
ko phan tich duoc nha bn
chuc bn hoc gioi
happy new year
