Question

Tìm x,y biết:

a) \(\left|x-3,5\right|+\left|y-\frac{1}{2}\right|=0\)

b) \(2-\left|x+1\right|=3-x\)

Answer 1

a) \(\left|x-3,5\right|+\left|y-\frac{1}{2}\right|=0\)

Ta có:

\(\left\{{}\begin{matrix}\left|x-3,5\right|\ge0\\\left|y-\frac{1}{2}\right|\ge0\end{matrix}\right.\forall xy.\)

\(\Rightarrow\left|x-3,5\right|+\left|y-\frac{1}{2}\right|=0\)

\(\Rightarrow\left\{{}\begin{matrix}x-3,5=0\\y-\frac{1}{2}=0\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=0+3,5\\y=0+\frac{1}{2}\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=3,5\\y=\frac{1}{2}\end{matrix}\right.\)

Vậy \(\left(x;y\right)\in\left\{3,5;\frac{1}{2}\right\}.\)

Chúc bạn học tốt!