2x2 + y2 -6x + 2xy - 2y +5 =0
=> x2 + 2xy + y2 + - 2x - 2y + 1 + x2 - 4x + 4 = 0
=> ( x + y)2 - 2( x + y) + 1 + ( x - 2)2 = 0
=> ( x + y - 1)2 +( x - 2)2 = 0
Do : ( x + y - 1)2 +( x - 2)2 lớn hơn hoặc bằng 0
Suy ra :
*( x + y - 1)2 = 0 => ( 2 - 1 + y)2 = 0 => y = -1
* (x - 2)2 = 0 => x = 2
Vậy,...