Question

Tìm số tự nhiên x , biết:

a) 4x^3 + 15 = 47

b)4.2^x - 3 = 125

Answer 1

a) \(4x^3+15=47\)

\(\Rightarrow4x^3=32\)

\(\Rightarrow x^3=8\)

\(\Rightarrow x^3=2^3\)

\(\Rightarrow x=2\)

Vậy \(x=2\)

b) \(4.2^x-3=125\)

\(\Rightarrow4.2^x=128\)

\(\Rightarrow2^x=32\)

\(\Rightarrow2^x=2^5\)

\(\Rightarrow x=5\)

Vậy \(x=5\)

Answer 2

a ) \(4x^3+15=47\)

\(\Leftrightarrow4x^3=32\)

\(\Leftrightarrow x^3=8\)

\(\Leftrightarrow x^3=2^3\)

\(\Leftrightarrow x=3\)

\(4.2^x-3=125\)

\(\Leftrightarrow4.2^x=128\)

\(\Leftrightarrow2^x=32\)

\(\Leftrightarrow2^x=2^5\)

\(\Leftrightarrow x=5\)