\(\Leftrightarrow x=\dfrac{49+20t}{11}\)
Để x nguyên thì \(49+20t⋮11\)
\(\Rightarrow44+5\left(1+4t\right)⋮11\)\(\Rightarrow4t+1=11k\left(k\in Z\right)\)
\(\Rightarrow t=\dfrac{11k-1}{4}\)\(\Rightarrow x=\dfrac{55k+44}{11}=5k+4\)
\(\Rightarrow55k+44-55k+5=0\)
\(\Rightarrow49=0\left(vl\right)\)
Vậy không tồn tại x,t thỏa mãn.