Áp dụng t/c của dãy tỉ số = nhau có:
\(\dfrac{x}{2}=\dfrac{y}{4}=\dfrac{z}{6}=\dfrac{x-y+z}{2-4+6}=\dfrac{8}{4}=2\)
\(\Rightarrow\left\{{}\begin{matrix}x=2\cdot2=4\\y=2\cdot4=8\\z=2\cdot6=12\end{matrix}\right.\)
Tim x, y, z biet
\(\dfrac{12x-15y}{2017}=\dfrac{20z-12x}{2018}=\dfrac{15y-20z}{2019}\) va x+y+z=48
a,\(\dfrac{y+z+1}{x}=\dfrac{z+x+2}{y}=\dfrac{x+y-3}{z}=\dfrac{1}{x+y+z}\)
b, 10x = 6y va 2x2 - y2 = -28
Tim x,y,z(cau a)
tim x,y ( cau b)
Tim x,y,z biet:
\(\dfrac{2x}{3}\) = \(\dfrac{3y}{4}\) = \(\dfrac{4z}{5}\) va -x-y-z=-49
\(\dfrac{x-1}{2}=\dfrac{y-2}{3}=\dfrac{z-3}{4}\) va 3x + 3y - z = 50
tim x, y ,z
tim x,y,z biet
\(\dfrac{x}{y}\) =\(\dfrac{3}{2}\) ; \(\dfrac{y}{z}\) = \(\dfrac{5}{7}\) va \(|2x-3y+5z|\) =1
\(\dfrac{x}{2}=\dfrac{y}{3}=\dfrac{z}{5}\)va xyz = 810
tim x,y,z
Bai 1: Tim x, y, z.
a) \(\dfrac{x}{-3}\) = \(\dfrac{y}{5}\) va x . y = \(\dfrac{-5}{27}\) .
b) \(\dfrac{x}{3}\) = \(\dfrac{y}{4}\) va \(\dfrac{y}{3}\) = \(\dfrac{z}{5}\) va x - y + z = 32
Tìm các số x, y, z biết:
a) \(\dfrac{x}{2}=\dfrac{y}{3};\dfrac{y}{5}=\dfrac{z}{4}\) và x + z - y = -49
b) \(\dfrac{x}{3}=\dfrac{y}{-2};\dfrac{x}{6}=\dfrac{z}{7}\) và 3x - z + 2y = 3
Lm hết nha mọi ngừi ^^
Tìm các số x,y,z biết:\(\dfrac{x}{2}=\dfrac{y}{4}=\dfrac{z}{6}\)và x-y+z=8
