Question

tim x,y,z biet

\(\dfrac{x}{y}\) =\(\dfrac{3}{2}\) ; \(\dfrac{y}{z}\) = \(\dfrac{5}{7}\) va ^{_{\(|2x-3y+5z|\) =1}}

Answer 1

ê

Answer 2

2x-3y+5z=1 hoặc =-1

TH1: \(\dfrac{x}{y}\)=\(\dfrac{3}{2}\)=>\(\dfrac{x}{3}\)=\(\dfrac{y}{2}\)=>\(\dfrac{x}{15}\)=\(\dfrac{y}{10}\)

\(\dfrac{y}{z}\)=\(\dfrac{5}{7}\)=>\(\dfrac{y}{5}\)=\(\dfrac{z}{7}\)=>\(\dfrac{y}{10}\)=\(\dfrac{z}{14}\)

\(\Rightarrow\)\(\dfrac{x}{15}\)=\(\dfrac{y}{10}\)=\(\dfrac{z}{14}\)=>\(\dfrac{2x}{30}\)=\(\dfrac{3y}{30}\)=\(\dfrac{5z}{70}\)

Áp dụng tính chát dãy tỉ số bằng nhau, ta có:

\(\dfrac{2x-3y+5z}{30-30+70}\)=\(\dfrac{1}{70}\)

=>x=1.15:7=\(\dfrac{3}{14}\)

y=\(\dfrac{1}{7}\)

z=\(\dfrac{1}{5}\)

TH2:............=-1 tự tính nhé làm tương tựmình còn phải ôn bài