b: \(=\dfrac{x+3}{\left(x-1\right)\left(x+1\right)}-\dfrac{1}{x\left(x+1\right)}\)
\(=\dfrac{x^2+3x-x+1}{x\left(x-1\right)\left(x+1\right)}\)
\(=\dfrac{\left(x+1\right)^2}{x\left(x-1\right)\left(x+1\right)}=\dfrac{x+1}{x\left(x-1\right)}\)
a: \(=\dfrac{x^2-9-x^2+9}{x\left(x-3\right)}=0\)