\(=\frac{\left(\sqrt{5}-2\right)^2}{\sqrt{5}\left(\sqrt{5}+2\right)\left(\sqrt{5}-2\right)}-\frac{\sqrt{5}-2}{\left(\sqrt{5}-2\right)\left(\sqrt{5}+2\right)}+\frac{1}{\sqrt{5}}\)
\(=\frac{9-4\sqrt{5}}{\sqrt{5}}+\frac{1}{\sqrt{5}}-\sqrt{5}+2=\frac{10-4\sqrt{5}}{\sqrt{5}}-\sqrt{5}+2\)
\(=2\sqrt{5}-4-\sqrt{5}+2=3\sqrt{5}-2\)