a: \(=\dfrac{3^3\left(2^3+2^2+1\right)}{-13}=-3^3=-27\)
b: \(=\left(\dfrac{12}{12}+\dfrac{8}{12}-\dfrac{3}{12}\right)\cdot\left(\dfrac{16}{20}-\dfrac{15}{20}\right)^2\)
\(=\dfrac{17}{12}\cdot\left(\dfrac{1}{20}\right)^2=\dfrac{17}{12\cdot400}=\dfrac{17}{4800}\)