\(2-\sqrt{3}=\dfrac{1}{2+\sqrt{3}}\)
\(3-2\sqrt{2}=\dfrac{1}{3+2\sqrt{2}}\)
mà \(2+\sqrt{3}< 2\sqrt{2}+3\)
nên \(2-\sqrt{3}>3-2\sqrt{2}\)
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\(2-\sqrt{3}=\dfrac{1}{2+\sqrt{3}}\)
\(3-2\sqrt{2}=\dfrac{1}{3+2\sqrt{2}}\)
mà \(2+\sqrt{3}< 2\sqrt{2}+3\)
nên \(2-\sqrt{3}>3-2\sqrt{2}\)