a: \(\dfrac{17}{30}=\dfrac{1564}{30\cdot92}\)
\(\dfrac{51}{92}=\dfrac{1530}{30\cdot92}\)
mà 1564>1530
nên 17/30>51/92
b: \(\dfrac{-45}{47}>-1>-\dfrac{31}{30}\)
c: \(\dfrac{67}{22}=3+\dfrac{1}{22}\)
\(\dfrac{152}{51}=3+\dfrac{1}{51}\)
mà 1/22>1/51
nên 67/22>152/51
=>22/67<51/152
d: 17/39>17/41
nên -17/39<-17/41
=>-18/39<-17/39<-17/41
so sánh: A = \(\dfrac{20}{39}+\dfrac{22}{27}+\dfrac{18}{43}\) và B = \(\dfrac{14}{39}+\dfrac{22}{29}+\dfrac{18}{41}\)
A = 17\(\dfrac{2}{31}\) - ( \(\dfrac{15}{17}\) + 6\(\dfrac{2}{31}\) )
B = ( 31\(\dfrac{6}{13}\) + 5\(\dfrac{9}{41}\) ) - 36\(\dfrac{6}{12}\)
C = 27\(\dfrac{51}{59}\) - ( 7\(\dfrac{51}{59}\) - \(\dfrac{1}{3}\) )
giúp em với em cảm ơn
SO SÁNH A VÀ B
a ) A=\(\dfrac{3}{8^3}+\dfrac{7}{^{ }8^4}\) B =\(\dfrac{7}{8^3}+\dfrac{3}{8^4}\)
b ) A=\(\dfrac{20}{39}+\dfrac{22}{27}+\dfrac{18}{43}\) B=\(\dfrac{14}{39}+\dfrac{22}{29}+\dfrac{18}{41}\)
Bai1 : tính hợp lí
A = 17\(\dfrac{2}{31}\) - ( \(\dfrac{15}{17}\) + 6\(\dfrac{2}{31}\) )
B = ( 31\(\dfrac{6}{13}\) + 5\(\dfrac{9}{41}\) ) - 36\(\dfrac{9}{41}\) ) - 36\(\dfrac{6}{13}\)
C = 27\(\dfrac{51}{59}\) - ( 7\(\dfrac{51}{59}\) - \(\dfrac{1}{3}\) )
bai2: Tính
A = \(\dfrac{1}{2.3}\) + \(\dfrac{1}{3.4}\) + \(\dfrac{1}{4.5}\) +...+ \(\dfrac{1}{49.50}\)
B = \(\dfrac{1}{37}\) + \(\dfrac{1}{7.11}\) + \(\dfrac{1}{11.15}\)+....+\(\dfrac{1}{23.27}\)
1. thực hiện phép tính
a. \(\dfrac{25}{7}\)+\(\dfrac{13}{21}\)-\(\dfrac{11}{7}\)+\(\dfrac{17}{21}\)+\(\dfrac{1}{3}\)
b. (\(\dfrac{1}{3}\)+\(\dfrac{12}{67}\)+\(\dfrac{13}{41}\))-(\(\dfrac{79}{67}\)-\(\dfrac{28}{41}\))
c. (\(\dfrac{11}{4}\).\(\dfrac{-5}{9}\)-\(\dfrac{4}{9}\).\(\dfrac{11}{4}\)).\(\dfrac{8}{33}\)
d. \(\dfrac{38}{45}\)-(\(\dfrac{8}{45}\)-\(\dfrac{17}{51}\)-\(\dfrac{3}{11}\))
So Sanh : \(\dfrac{-22}{45}\)và\(\dfrac{-51}{103}\)
So Sánh : S = \(\dfrac{1}{5}+\dfrac{1}{9}+\dfrac{1}{10}+\dfrac{1}{41}+\dfrac{1}{42}\) và \(\dfrac{1}{2}\)
Bài 1 : tìm x
a) \(\dfrac{2012-x}{25}+\dfrac{2053-x}{23}+\dfrac{2070-x}{21}+\dfrac{2083-x}{19}-10=0\\ \)
b) \(x+\dfrac{13}{12}+\dfrac{21}{20}+\dfrac{31}{30}+\dfrac{43}{42}+\dfrac{57}{56}+\dfrac{73}{72}+\dfrac{91}{90}=0\)
1. So sánh các tích sau hợp lý nhất:
P = \(\left(-\dfrac{21}{34}\right)\)\(\left(-\dfrac{13}{27}\right)\)\(\dfrac{7}{9}\)
Q = \(\left(-0,5\right)\)\(\dfrac{3}{19}\)\(\left(-\dfrac{24}{41}\right)\)\(\left(\dfrac{8}{31}\right)\)
M = \(\dfrac{-6}{17}.\dfrac{-5}{17}.\) ... \(.\dfrac{5}{17}.\dfrac{6}{17}\)
2. Tính hợp lý:
A = \(\left(-\dfrac{3}{11}\right).\dfrac{7}{10}.\dfrac{11}{-13}.\left(-20\right)\)
B = \(\dfrac{-4}{9}:\dfrac{2}{13}+\left(\dfrac{-5}{18}\right).\dfrac{2}{13}\)
C = \(\left(2\dfrac{1}{15}.\dfrac{3}{19}.\dfrac{2}{31}\right):\left(-\dfrac{5}{19}\right)\)
Help me!
