Question

SO SÁNH A VÀ B

a ) A=\(\dfrac{3}{8^3}+\dfrac{7}{^{ }8^4}\) B =\(\dfrac{7}{8^3}+\dfrac{3}{8^4}\)

b ) A=\(\dfrac{20}{39}+\dfrac{22}{27}+\dfrac{18}{43}\) B=\(\dfrac{14}{39}+\dfrac{22}{29}+\dfrac{18}{41}\)

Answer 1

a, Ta có:

A= \(\dfrac{3}{8^3}+\dfrac{7}{8^4}=\dfrac{3}{8^3}+\dfrac{3}{8^4}+\dfrac{4}{8^4}\)

B= \(\dfrac{7}{8^3}+\dfrac{3}{8^4}=\dfrac{3}{8^3}+\dfrac{4}{8^3}+\dfrac{3}{8^4}\)

Vì \(\dfrac{4}{8^4}< \dfrac{4}{8^3}\) nên A < B.

b, Ta có:

\(\dfrac{20}{39}>\dfrac{14}{39}\)

\(\dfrac{22}{27}>\dfrac{22}{29}\)

\(\dfrac{18}{43}< \dfrac{18}{41}\)

\(\Rightarrow\)\(\dfrac{20}{39}+\dfrac{22}{27}+\dfrac{18}{43}>\dfrac{14}{39}+\dfrac{22}{29}+\dfrac{18}{41}\)

Hay A > B