A = \(\frac{x+3}{2x-2}-\frac{4}{x^2-1}.\frac{x+1}{2}\)
= \(\frac{\left(x+3\right)\left(x+1\right)}{2\left(x^2-1\right)}-\frac{4\left(x+1\right)}{2\left(x^2-1\right)}\)
=\(\frac{\left(x+1\right)\left(x+3-4\right)}{2\left(x^2-1\right)}\)
= \(\frac{\left(x^2-1\right)}{2\left(x^2-1\right)}\)
= \(\frac{1}{2}\)