Question

Rút gọn phân số \(\dfrac{9^{20}.2^{27}.22^5}{4^8.18^{18}.33^4}\). Ta đc phân số tối giản là \(\dfrac{a}{4}\). a = ?

Answer 1

a = 11

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Answer 2

a=11

Answer 3

x = 11

Answer 4

Ta có:

\(\dfrac{9^{20}\times2^{27}\times22^5}{4^8\times18^{18}\times33^4}=\dfrac{\left(3^2\right)^{20}\times2^{27}\times\left(2\times11\right)^5}{\left(2^2\right)^8\times\left(2\times3^2\right)^{18}\times\left(3\times11\right)^4}=\dfrac{3^{40}\times2^{27}\times2^5\times11^5}{2^{16}\times2^{18}\times3^{36}\times3^4\times11^4}=\dfrac{2^{32}\times3^{40}\times11^5}{2^{34}\times3^{40}\times11^4}=\dfrac{11}{4}\)

\(\Rightarrow\dfrac{a}{4}=\dfrac{11}{4}\Rightarrow a=11\)

Vậy \(a=11\).