Question

Rút gọn các căn bậc hai sau

\(\sqrt{\frac{9}{4}-\sqrt{2}}\)

\(\sqrt{\frac{129}{16}+\sqrt{2}}\)

\(\sqrt{3+\sqrt{8}}\)

\(\sqrt{\frac{289+4\sqrt{72}}{16}}\)

\(\sqrt{2}\sqrt{4+\sqrt{15}}\)

Answer 1

\(\sqrt{\frac{9-4\sqrt{2}}{4}}=\frac{\sqrt{\left(2\sqrt{2}-1\right)^2}}{2}=\frac{2\sqrt{2}-1}{2}\)

\(\sqrt{\frac{129+16\sqrt{2}}{16}}=\sqrt{\frac{\left(8\sqrt{2}+1\right)^2}{16}}=\frac{8\sqrt{2}+1}{4}\)

\(\sqrt{3+2\sqrt{2}}=\sqrt{\left(\sqrt{2}+1\right)^2}=\sqrt{2}+1\)

\(\sqrt{\frac{289+4\sqrt{72}}{16}}=\frac{\sqrt{\left(12\sqrt{2}+1\right)^2}}{4}=\frac{12\sqrt{2}+1}{4}\)

\(\sqrt{8+2\sqrt{15}}=\sqrt{\left(\sqrt{5}+\sqrt{3}\right)^2}=\sqrt{5}+\sqrt{3}\)