Question

1. Áp dụng quy tắc khai phương 1 thương, tính:

\(\frac{3\sqrt{128}}{\sqrt{2}}\)

2. Tính:

a. \(\left(\sqrt{32}-\sqrt{50}+\sqrt{8}\right):\sqrt{2}\)

b. \(\left(5\sqrt{48}-3\sqrt{27}+2\sqrt{12}\right):\sqrt{3}\)

c. \(\left(\sqrt{6}-\sqrt{2}\right)\sqrt{2+\sqrt{3}}\)

f. \(\left(4+\sqrt{15}\right)\left(\sqrt{10}-\sqrt{6}\right)\sqrt{4-\sqrt{15}}\)

Answer 1

\(\frac{3\sqrt{128}}{\sqrt{2}}=\frac{\sqrt{9.128}}{\sqrt{2}}=\sqrt{\frac{1152}{2}}=\sqrt{576}=24\)