Question

Phân tích các đa thức sau thành nhân tử ( phương pháp đặt thừa số chung )

1) -4a - 8b - 12c

2) 9ab - 18a + 9

3) -ax² - ax - a

4) -2a² b - 4ab² - 6ab

5) mxy - m² x + my

6) 12x³ y - 6xy + 3x

7) mx( a + b ) - m( a + b )

8) x^{m + 2} - x^{m + 1}

9) 5x² y( x - 7 ) - 5xy( 7 - x )

Các bạn giải nhanh cho mình đi. Mình đang cần gấp lắm

Answer 1

1) \(-4a-8b-12c=-4\cdot\left(a+2b+3c\right)\)

2) \(9ab-18a+9=9\cdot\left(ab-2a+1\right)\)

3) \(-ax^2-ax-a=-a\left(x^2+x+1\right)\)

4) \(-2a^2b-4ab^2-6ab=-2ab\left(a+2b+3\right)\)

5) \(mxy-m^2x+my=m\left(xy-mx+y\right)\)

6) \(12x^3y-6xy+3x=3x\left(4x^2y-2y+1\right)\)

7) \(mx\left(a+b\right)-m\left(a+b\right)=m\left(a+b\right)\left(x-1\right)\)

8) \(x^{m+2}-x^{m+1}=x^{m+1}\left(x-1\right)\)

9) \(5x^2y\left(x-7\right)-5xy\left(7-x\right)=5x^2y\left(x-7\right)+5xy\left(x-7\right)=5xy\left(x-7\right)\left(x+1\right)\)

Answer 2

1) -4a - 8b - 12c = -4 ( a + 2b + 3c)

2) 9ab - 18a + 9 = 9 ( ab - a +1 )

3) -ax² - ax - a = -a ( x² + x + 1)

4) - 2a²b - 4ab² - 6ab = -2ab ( a + 2b + 3 )

5)mxy - m²x + my = m ( xy - mx + y )

6)12x³y - 6xy + 3x = 3x ( 4x²y - 2y + 1 )

7) mx ( a+ b) - m (a+b) = (a+b) ( mx-m ) = m ( a+b)(x-1)

8) x^m+2 - x^m+1 = x^{m + 1} (x -1 )

9) 5x²y ( x-7 ) - 5xy ( 7 -x )

= 5x²y ( x -7 ) + 5xy ( x-7 )

= 5xy ( x +1 ) (x-7)