Question

\(\left(3x-1\right)\cdot\left(2x+7\right)-\left(x+1\right)\cdot\left(6x-5\right)=16\)

Answer 1

\(\left(3x-1\right)\left(2x+7\right)-\left(x+1\right)\left(6x-5\right)=16\)

\(\Leftrightarrow6x^2+19x-7-6x^2-x+5=16\)

\(\Leftrightarrow18x=18\)

\(\Leftrightarrow x=1\)

Answer 2

Giải:

\(\left(3x-1\right)\left(2x+7\right)-\left(x+1\right)\left(6x-5\right)=16\)

\(\Leftrightarrow6x^2-2x+21x-7-\left(6x^2+6x-5x-5\right)=16\)

\(\Leftrightarrow6x^2+19x-7-\left(6x^2+x-5\right)=16\)

\(\Leftrightarrow6x^2+19x-7-6x^2-x+5=16\)

\(\Leftrightarrow18x-2=16\)

\(\Leftrightarrow18x=18\)

\(\Leftrightarrow x=1\)

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