\(\left(3x-2\right)\left(4x-5\right)-\left(2x-1\right)\left(6x+2\right)=0\)
\(\Leftrightarrow12x^2-15x-8x+10-\left(12x^2+4x-6x-2\right)=0\)
\(\Leftrightarrow12x^2-15x-8x+10-12x^2-4x+6x+2=0\)
\(\Leftrightarrow-21x+12=0\Leftrightarrow21x=12\Leftrightarrow x=\dfrac{12}{21}=\dfrac{4}{7}\)
vậy \(x=\dfrac{4}{7}\)