Ta có: MN//PQ
nên \(\widehat{M}+\widehat{Q}=180^0\)
mà \(\widehat{M}-\widehat{Q}=40^0\)
nên \(2\cdot\widehat{M}=220^0\)
\(\Leftrightarrow\widehat{M}=110^0\)
\(\Leftrightarrow\widehat{Q}=70^0\)
Ta có: \(\widehat{N}+\widehat{P}=180^0\)
\(\Leftrightarrow\widehat{P}\cdot\dfrac{9}{5}=180^0\)
\(\Leftrightarrow\widehat{P}=100^0\)
\(\Leftrightarrow\widehat{N}=80^0\)