Question

Giúp mình với!!!

Answer 1

Ta có: \(\dfrac{1}{\sqrt{7-\sqrt{24}}-1}-\dfrac{1}{\sqrt{7+\sqrt{24}}-1}\)

\(=\dfrac{1}{\sqrt{6}-1-1}-\dfrac{1}{\sqrt{6}+1-1}\)

\(=\dfrac{1}{\sqrt{6}-2}-\dfrac{1}{\sqrt{6}}\)

\(=\dfrac{\sqrt{6}+2}{2}-\dfrac{\sqrt{6}}{6}\)

\(=\dfrac{3\sqrt{6}+6-\sqrt{6}}{6}\)

\(=\dfrac{2\sqrt{6}+6}{6}\)