Question

giải phương trình

x+1/9 + x+2/8=x+3/7 + x+4/6

Answer 1

\(\frac{x+1}{9}+\frac{x+2}{8}=\frac{x+3}{7}+\frac{x+4}{6}\)

\(\Leftrightarrow\) \(\frac{x+1}{9}+1+\frac{x+2}{8}+1=\frac{x+3}{7}+1+\frac{x+4}{6}+1\)

\(\Leftrightarrow\) \(\frac{x+10}{9}+\frac{x+10}{8}=\frac{x+10}{7}+\frac{x+10}{6}\)

\(\Leftrightarrow\) \(\frac{x+10}{9}+\frac{x+10}{8}-\frac{x+10}{7}-\frac{x+10}{6}=0\)

\(\Leftrightarrow\) (x + 10)(\(\frac{1}{9}+\frac{1}{8}-\frac{1}{7}-\frac{1}{6}\)) = 0

\(\Leftrightarrow\) x + 10 = 0

\(\Leftrightarrow\) x = -10

Vậy S = {-10}

Chúc bn học tốt!!