ĐKXĐ: ....
\(VT=\sqrt{x}+\sqrt{y-1}+\sqrt{z-2}\le\dfrac{1}{2}\left(x+1\right)+\dfrac{1}{2}\left(y-1+1\right)+\dfrac{1}{2}\left(z-2+1\right)\)
\(VT\le\dfrac{1}{2}\left(x+y+z\right)\)
Dấu "=" xảy ra khi và chỉ khi:
\(\left\{{}\begin{matrix}x=1\\y-1=1\\z-2=1\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}x=1\\y=2\\z=3\end{matrix}\right.\)