Ta có: \(\sqrt{5-3x}=\sqrt{2x+8}\)
\(\Leftrightarrow\left(\sqrt{5-3x}\right)^2=\left(\sqrt{2x+8}\right)^2\)
\(\Leftrightarrow5-3x=2x+8\)
\(\Leftrightarrow5-3x-2x-8=0\)
\(\Leftrightarrow-5x-3=0\)
\(\Leftrightarrow-5x=3\)
hay \(x=\frac{3}{-5}=\frac{-3}{5}\)
Vậy: \(S=\left\{\frac{-3}{5}\right\}\)