Question

giải phương trình sau :

\(\dfrac{36}{x}\) +\(\dfrac{36}{x-12}\) =\(\dfrac{9}{2}\)

giúp mình nhanh nha

Answer 1

\(\dfrac{36}{x}+\dfrac{36}{x-12}=\dfrac{9}{2}\)

\(\Rightarrow72\left(x-12\right)+72x\left(x-12\right)-x\left(x-12\right)=0\)

\(\Leftrightarrow\left(x-12\right)\left(72+72x-x\right)=0\)

\(\Leftrightarrow\left(x-12\right)\left(72+71x\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x-12=0\\72+71x=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=12\\x=\dfrac{-72}{71}\end{matrix}\right.\)

Vậy phương trình có nghiệm x = 12 hoặc x = \(\dfrac{-72}{71}\) .

Answer 2

Tick cho e nhá