Question

giải các phương trình sau : \(\dfrac{2x-3}{4}+2=\dfrac{1-x}{6}\)

Answer 1

\(\dfrac{2x-3}{4}+2=\dfrac{1-x}{6}\)

\(\dfrac{\left(2x-3\right).6}{4.6}+\dfrac{2.16}{16.1}=\dfrac{\left(1-x\right).4}{6.4}\)

khử mẫu:

=>(2x-3).6+32=(1-x).4

=>12x-18+32=4x-1

=>12x-18+32-4x+1=0

=>8x+13=0

=>x=-13:8

=>x=\(-\dfrac{13}{8}\)

Answer 2

\(6x-9+24=2-2x\Leftrightarrow8x=-13\Leftrightarrow x=-\dfrac{13}{8}\)