giải phương trình:
\(\left(2x+3\right)\left(\dfrac{3x+8}{2-7x}+1\right)=\left(x-5\right)\left(\dfrac{3x+8}{2-7x}+1\right)\)
Giải các phương trình :
a) \(\dfrac{1}{2x-3}-\dfrac{3}{x\left(2x-3\right)}=\dfrac{5}{x}\)
b) \(\dfrac{x+2}{x-2}-\dfrac{1}{x}=\dfrac{2}{x\left(x-2\right)}\)
c) \(\dfrac{x+1}{x-2}+\dfrac{x-1}{x+2}=\dfrac{2\left(x^2+2\right)}{x^2-4}\)
d) \(\left(2x+3\right)\left(\dfrac{3x+8}{2-7x}+1\right)=\left(x-5\right)\left(\dfrac{3x+8}{2-7x}+1\right)\)
Giair các phương trình sau
\(a,\dfrac{3x^2+7x-10}{x}=0\) \(b,\dfrac{4x-17}{2x^2+1}=0\) \(c,\dfrac{\left(x^2+2x\right)-\left(3x-6\right)}{x+2}=0\)
\(d,\dfrac{x^2-x-6}{x-3}=0\) \(e,\dfrac{2x-5}{x+5}=3\) \(f,\)\(\dfrac{5}{3x+2}=2x-1\)
\(g,\dfrac{x^2-6}{x}=x+\dfrac{3}{2}\) \(h,\dfrac{4}{x-2}-x+2=0\)
Giups mình với , mik đang cần gấp
\(\dfrac{t+3}{t-2}+\dfrac{t-2}{t+3}=\dfrac{5t+15}{t^2+t-6}\)
\(\left(2x+3\right)\left(\dfrac{3x+8}{2-7x}+1\right)=\left(x-5\right)\left(\dfrac{3x+8}{2-7x}+1\right)\)
giúp mình vs. mai thày kiểm tra vở rùi
mơn các bạn nhiều
Giải các phương trình sau :
a) \(\dfrac{9x-0,7}{4}-\dfrac{5x-1,5}{7}=\dfrac{7x-1,1}{3}-\dfrac{5\left(0,4-2x\right)}{6}\)
b) \(\dfrac{3x-1}{x-1}-\dfrac{2x+5}{x+3}=1-\dfrac{4}{\left(x-1\right)\left(x+3\right)}\)
c) \(\dfrac{3}{4\left(x-5\right)}+\dfrac{15}{50-2x^2}=-\dfrac{7}{6\left(x+5\right)}\)
d) \(\dfrac{8x^2}{3\left(1-4x^2\right)}=\dfrac{2x}{6x-3}-\dfrac{1+8x}{4+8x}\)
Giải các phương trình sau :
a) \(\left(x+2\right)\left(x^2-3x+5\right)=\left(x+2\right)x^2\)
b) \(\dfrac{-7x^2+4}{x^3+1}=\dfrac{5}{x^2-x+1}-\dfrac{1}{x+1}\)
c) \(2x^2-x=3-6x\)
d) \(\dfrac{x-2}{x+2}-\dfrac{3}{x-2}=\dfrac{2\left(x-11\right)}{x^2-4}\)
Bài 1: Giải các phương trình sau:
a. 7-( 2x + 4 ) = - (x+4)
b.\(\dfrac{2x}{x+1}=\dfrac{x^2-x+8}{\left(x+1\right)\left(x-4\right)}\)
c.\(\dfrac{2\left(3x+5\right)}{3}-\dfrac{x}{2}=5-\dfrac{3\left(x+1\right)}{4}\)
Giải các phương trình sau bằng cách đưa về phương trình tích :
a) \(\left(2x+1\right)\left(3x-2\right)=\left(5x-8\right)\left(2x+1\right)\)
b) \(4x^2-1=\left(2x+1\right)\left(3x-5\right)\)
c) \(\left(x+1\right)^2=4\left(x^2-2x+1\right)\)
d) \(2x^3+5x^2-3x=0\)
a) \(9x^2-1=\left(3x-1\right)\left(5x+8\right)\)
b) \(2x^3-5x^2+3x=0\)
c) \(9x^2-16-x\left(3x+4\right)=0\)
d) \(\dfrac{5x+4}{3}-1=\dfrac{3x-2}{4}\)