\(\left\{{}\begin{matrix}\dfrac{4}{x+y-1}-\dfrac{5}{2x-y+3}=\dfrac{5}{2}\\\dfrac{3}{x+y-1}-\dfrac{1}{2x-y+3}=\dfrac{7}{5}\end{matrix}\right.\)
Đặt x+y-1=a; 2x-y+3=b
Theo đề, ta có:
4/a-5/b=5/2 và 3/a-1/b=7/5
=>a=22/9; b=-110/19
=>x+y=31/9; 2x+y=-110/19-3=-167/19
=>x=-2092/171; y=2681/171