\(\left(x^2-5\right)\left(x+2\right)+5x=2x^2+17\)
\(\Leftrightarrow x^2\left(x+2\right)-5\left(x+2\right)+5x-2x^2-17=0\)
\(\Leftrightarrow x^3+2x^2-5x-10+5x-2x^2-17=0\)
\(\Leftrightarrow x^3-3^3=0\)
\(\Leftrightarrow\left(x-3\right)\left(x^2+3x+9\right)=0\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}x-3=0\\x^2+3x+9=0\end{array}\right.\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}x=3\left(tm\right)\\\left(x+\frac{3}{2}\right)^2+\frac{27}{4}>0\left(loai\right)\end{array}\right.\)
M.n giúp mk nhanh nka!
Vì mk gửi câu hỏi bị lỗi nên nhờ Nguyễn Hoàng Gia Bảo đăng giúp
tuong sao anh bao hok lop 8
hoa ra la......
