\(\frac{x+1}{2018}+\frac{x+1}{2019}=\frac{x+1}{2020}+\frac{x+1}{2021}\Leftrightarrow\frac{x+1}{2018}+\frac{x+1}{2019}-\frac{x+1}{2020}-\frac{x+1}{2021}=0\)
\(\Leftrightarrow\left(x+1\right)\left(\frac{1}{2018}+\frac{1}{2019}-\frac{1}{2020}-\frac{1}{2021}\right)=0\Leftrightarrow x+1=0\Leftrightarrow x=-1\)
KL: ................
Giải phương trình sau:
\(\frac{x+1}{2018}\)+\(\frac{x+2}{2019}\)=\(\frac{x+3}{2020}\)+\(\frac{x+4}{2021}\)
Giải phương trình
a , \(\frac{3x+2}{x-1}+\frac{2x-4}{x+2}=5\)
b , \(\frac{4-3x}{1-x^2}-\frac{2}{x+1}=0\)
c , \(\frac{x+5}{x-1}=\frac{x+1}{x-3}-\frac{8}{x^2-4x+3}\)
d , \(\frac{x+1}{9}+\frac{x+2}{8}=\frac{x+3}{7}+\frac{x+4}{6}\)
e ,\(\frac{x}{2016}+\frac{x+1}{2019}+\frac{x+2}{2018}+\frac{x+3}{2019}+\frac{x+4}{2020}=5\)
Cần gấp giúp nhanh hộ mình với ạ !!!!
Giải các phương trình:
a)\(\frac{x+5}{x-5}-\frac{x-5}{x+5}=\frac{20}{x^2}-25\)
b) x2+ 6x+9= 144
c) \(\frac{2-x}{2016}-1=\frac{1-x}{2017}-\frac{x}{2018}\)
( mink đag cần gấp)
\(\frac{x-5}{2016}\)+ \(\frac{x-4}{2017}\)= \(\frac{x-3}{2018}\)+ \(\frac{x-2}{2019}\)
Giải toán lớp 8
1. \(\frac{1-6x}{x-2}+\frac{9x+4}{x+2}=\frac{x\left(3x-2\right)+1}{x^2-4}\)
2. \(\frac{1}{x-1}-\frac{3x^2}{x^3-1}=\frac{2x}{x^2+x+1}\)
3. \(\frac{1-6x}{x-2}+\frac{9x+4}{x+2}=\frac{x\left(3x-2\right)+1}{x^2-4}\)
\(\frac{1}{x-1}+\frac{1}{x-2}=\frac{1}{x+2}+\frac{1}{x+1}\)
Giải các phương trình sau:
a) \(\left(x-3\right)\left(1-x\right)=\left(2x-3\right)\left(x+5\right)\)
b) \(\frac{3}{5x-1}+\frac{2}{3-5x}=\frac{4}{\left(1-5x\right)\left(x-3\right)}\)
c) \(\frac{x+1}{x^2+x+1}-\frac{x-1}{x^2-x-1}=\frac{3}{x\left(x^4+x^2+1\right)}\)
d) \(\frac{m-3}{m+3}-\frac{1-3m}{1+3m}-1\)
e)\(\frac{x}{3+x}-\frac{x}{x-3}=\frac{1}{9-x^2}\)
a) x(x+1)-(x+2)(x-3)=7
b) \(\frac{x-3}{x+1}=\frac{x^2}{x^2-1}\)
c) \(\frac{1}{x+2}-\frac{4}{x-3}=\frac{10}{\left(x+2\right)\left(x-3\right)}\)
d) \(\frac{1}{x-2}+\frac{x-3}{x+2}=1\)
\left(1-\frac{x-1}{x+1}\right)\left(x+2\right)=\frac{x+1}{x-1}+\frac{x-1}{x+1}
