\(\frac{3x+2}{2}-\frac{3x+1}{6}=2x+\frac{5}{3}\)
=> \(\frac{3.\left(3x+2\right)}{6}-\frac{3x+1}{6}=\frac{12x}{6}+\frac{10}{6}\)
=> \(9x+6-3x-1=12x+10\)
=> 9x - 3x - 12x = -6 + 1 + 10
=> -6x = 5
=> x = \(\frac{-5}{6}\)
Giải:
Ta có: \(\frac{3x+2}{2}-\frac{3x+1}{6}=2x+\frac{5}{3}\)
\(\Leftrightarrow\frac{9x+6}{6}-\frac{3x+1}{6}=\frac{6x}{3}+\frac{5}{3}\)
\(\Leftrightarrow\frac{6x+5}{6}=\frac{6x+5}{3}\)
\(\Leftrightarrow18x+15=36x+30\)
\(\Leftrightarrow18x=-15\)
\(\Leftrightarrow x=\frac{-5}{6}\)
Vậy phương trình có nghiệm là x = \(-\frac{5}{6}\)
Chúc bạn học tốt@@
