\(\dfrac{2x-1}{4x^2+2x+1}+\dfrac{2}{2x-1}=\dfrac{-8x-2}{\left(2x-1\right)\left(4x^2+2x+1\right)}\)
\(\Leftrightarrow4x^2-4x+1+8x^2+4x+2=-8x-2\)
\(\Leftrightarrow12x^2+3+8x+2=0\)
\(\Leftrightarrow12x^2+8x+5=0\)
\(\text{Δ}=8^2-4\cdot12\cdot5=64-240< 0\)
DO đo: Phương trình vô nghiệm