\(\dfrac{-1}{3}+1=\dfrac{-1}{3}+\dfrac{3}{3}=\dfrac{-1+3}{3}=\dfrac{2}{3}\)
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Bài 1: Tập hợp Q các số hữu tỉ
Các câu hỏi tương tự
11) dfrac{1}{3}x + dfrac{1}{5} - dfrac{1}{2}x 1dfrac{1}{4}
12) dfrac{3}{2}( x + dfrac{1}{2}) - dfrac{1}{8}x dfrac{1}{4}
13) dfrac{3}{5}( x + dfrac{1}{3}) - dfrac{1}{3}( x - dfrac{1}{2}) 1dfrac{1}{3}
14) dfrac{2}{5}( x + dfrac{1}{2}) dfrac{3}{4}( x - dfrac{1}{5})
Giup mik nha mik cần gấp
Đọc tiếp
11) \(\dfrac{1}{3}\)x + \(\dfrac{1}{5}\) - \(\dfrac{1}{2}\)x = 1\(\dfrac{1}{4}\)
12) \(\dfrac{3}{2}\)( x + \(\dfrac{1}{2}\)) - \(\dfrac{1}{8}\)x = \(\dfrac{1}{4}\)
13) \(\dfrac{3}{5}\)( x + \(\dfrac{1}{3}\)) - \(\dfrac{1}{3}\)( x - \(\dfrac{1}{2}\)) = 1\(\dfrac{1}{3}\)
14) \(\dfrac{2}{5}\)( x + \(\dfrac{1}{2}\)) = \(\dfrac{3}{4}\)( x - \(\dfrac{1}{5}\))
Giup mik nha mik cần gấp
\(\dfrac{0,75+\dfrac{3}{5}-\dfrac{3}{7}-\dfrac{3}{13}}{2,75+2\dfrac{1}{5}-\dfrac{11}{7}-\dfrac{11}{3}}-\dfrac{0,75-\dfrac{3}{11}-\dfrac{1}{3}}{\dfrac{5}{22}-0,625+\dfrac{5}{18}}\)
Thực hiện phép tính :
a ) \(1-\dfrac{1}{2}:\dfrac{-3}{2}+\dfrac{2}{3}\)
b ) \(\dfrac{-3}{4}-\dfrac{-7}{2}+\dfrac{2}{-3}\)
c ) \(0,25-3\dfrac{1}{2}:\dfrac{1}{2}+\dfrac{-3}{4}.\dfrac{2}{-3}\)
7 tháng 10 2021 lúc 9:33
Chứng minh rằng :
\(\dfrac{1}{1\cdot2}+\dfrac{1}{3\cdot4}+...+\dfrac{1}{49\cdot50}=\dfrac{1}{26}+\dfrac{1}{27}+...+\dfrac{1}{50}\)
Chứng minh rằng:
a) \(\dfrac{1}{2!}+\dfrac{2}{3!}+\dfrac{3}{4!}+...\dfrac{2018}{2019!}\)<1
b) \(\dfrac{1.2-1}{2!}+\dfrac{2.3-1}{3!}+...+\dfrac{999.1000-1}{1000!}\)<2
Tìm x, biết:
a) \(\dfrac{-3}{7}+x=\dfrac{1}{3}\)
b) \(\dfrac{3}{4}+\dfrac{1}{4}:x=\dfrac{2}{5}\)
c) \(1\dfrac{1}{3}:0,8=\dfrac{2}{3}:0,1x\)
d) \(\left|x-3\right|=\dfrac{1}{2}\)
Chứng minh rằng: \(\dfrac{1}{1.4}+\dfrac{1}{4.7}+\dfrac{1}{7.10}+...+\dfrac{1}{97.100}< \dfrac{1}{3}\)
a) -12=\(\dfrac{-12}{1}\)
b) 2,1=\(\dfrac{21}{10}\)
c) -7\(\dfrac{1}{3}\)=\(\dfrac{-22}{3}\)
d) 19%=\(\dfrac{19}{100}\)
Tìm x:
a) \(\dfrac{2}{3}\) - \(\dfrac{1}{3}\) . ( x - \(\dfrac{3}{2}\) ) - \(\dfrac{1}{2}\) . ( 2x + 1 ) = 5
b) ( x + \(\dfrac{1}{2}\) ) . ( \(\dfrac{3}{4}\) - x ) = 0
c) \(\dfrac{2x-1}{-3+2}\) = 0
1+\(\dfrac{1}{1+2}\)+\(\dfrac{1}{1+2+3}\)+...+\(\dfrac{1}{1+2+3+...+2012}\)