Gọi d là ƯCNL( 2n+1; 2n+3) ( \(d\in N^{\text{*}}\))
Ta có: \(\left\{{}\begin{matrix}2n+1⋮d\\2n+3⋮d\end{matrix}\right.\)
\(\Rightarrow2n+3-\left(2n+1\right)⋮d\)
\(\Rightarrow2⋮d\)
\(\Rightarrow d\in\left\{1;2\right\}\)
Mà 2n+1, 2n+3 là số lẻ
=> d=1
=> Đpcm