Lời giải:
Ta có:
\(A=x^{1970}+x^{1930}+x^{1980}=x^{1930}(x^{50}+x^{40}+1)\)
Xét \(x^{50}+x^{40}+1=x^{30}(x^{20}+x^{10}+1)-(x^{30}-1)\)
\(=x^{30}(x^{20}+x^{10}+1)-(x^{10}-1)(x^{20}+x^{10}+1)\)
\(=(x^{20}+x^{10}+1)(x^{30}-x^{10}+1)\vdots x^{20}+x^{10}+1\)
Vì \(x^{50}+x^{40}+1\vdots x^{20}+x^{10}+1\Rightarrow A\vdots x^{20}+x^{10}+1\)
Do đó ta có đpcm.