Có: `\hat{B}=4\hat{C}=>\hat{C}=1/4\hat{B}`
Xét t/g `ABCD` có: `\hat{A}+\hat{B}+\hat{C}+\hat{D}=360^o`
`=>2\hat{B}+\hat{B}+1/4\hat{B}+\hat{B}+20^o=360^o`
`=>17/4\hat{B}=340^o`
`=>\hat{B}=80^o`
`->{(\hat{A}=2.80^o =160^o ),(\hat{C}=1/4 .80^o =20^o ),(\hat{D}=80^o +20^o =100^o):}`