\(m\ne5\)
\(\Delta'=\left(m-1\right)^2-m\left(m-5\right)=3m+1>0\Rightarrow m>-\frac{1}{3}\)
Đặt \(f\left(x\right)=\left(m-5\right)x^2+2\left(m-1\right)x+m\)
Để \(x_1< 1< x_2\Leftrightarrow\left(m-5\right).f\left(1\right)< 0\)
\(\Leftrightarrow\left(m-5\right)\left(m-5+2m-2+m\right)< 0\)
\(\Leftrightarrow\left(m-5\right)\left(4m-7\right)< 0\)
\(\Rightarrow\frac{7}{4}< m< 5\)